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Full Name | alex col |
Organization | tel integration |
Job Title | development engineer |
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Hi there 😀 i am sorry for re opening this discussion but i was just wondering if there are any ideas… why do i see the same Q-factor for cases 1 and 2 (having an “interfering signal” & without the “interfering signal”)? Is there a way to simulate the effect and see the difference?
Thanks 😀
Any other ideas guys?:)
When filtering out the “interfering signal” from the spectral light source, it makes sense that the Q-factor increases, right?
I wonder if this can be somehow simulated…
Thank you 😀
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Thank you for the reply Damian!!
I followed your instructions so now I do get “one signal”. nevertheless I still get the same Q-factor regardless if I filter out or not the spectral light source witch is quite confusing… Any other idea?
Hello Marek, you can find the layout picture above.. so any ideas…?
No matter if the signal for the Spectral Light Source 2 is filtered or not (refer to the snapshots attached in a previous mail from Spectrum Analyzer 4) the Q-factor remains the same.
This is not what I would expect though…
Ok for some reason I cannot attach I just hope you nevertheless get it 😀
Cheers!
and the attached … 😀
and the attached…
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Thank you for the reply Damian!
Yes, as you can see there is a passband filter before the receiver. Changing the transmitting wavelength of the light source at the bottom left corner I run two different simulations. First having the “interfering” lightsource within the pass band (thus not filtered) and then moving the lightsource out of the pass band (thus filtering it out).
My question is why is the Q factor in both cases the same?
p.s apparently I am at the wrong thread – sorry cannot edit it, hopefully a mod will fix it 🙂